Choose the equation of the line passing through the point (6, -2) and parallel to y = x + 7.
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OpenStudy (anonymous):
y = x + 8
y = x - 4
y = x + 4
y = x - 8
OpenStudy (souvik):
the line parallel to y=x+7 has an equation y=x+k where k is some constant...
now put x=6 and y=-2 and find k..
OpenStudy (anonymous):
slope of y=x+7 is 1
so the line passing throw (6,-2) is parallel to y=x+7 so ,slopes are equal m1=m2
now equation of a line passing through (6,-2) and slope 1 is
(y-y1)=m(x-x1)
y+2=1(x-6)
x-y-8=0
OpenStudy (anonymous):
I don't under stand
OpenStudy (anonymous):
so answer is y=x-8
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OpenStudy (anonymous):
yeah but I don't get how you did it
OpenStudy (souvik):
parallel lines have same slope....right?@lexi123479
OpenStudy (anonymous):
as the line y=x+7 and the line we have to find are parallel they have same slopes
OpenStudy (anonymous):
so find the slope of y=x+7
OpenStudy (anonymous):
hence it is the slope of the line we have to find
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OpenStudy (anonymous):
so we got the slope and point is given with point slope form find the equation