Choose the equation of the line passing through the point (6, -2) and parallel to y = x + 7.
y = x + 8 y = x - 4 y = x + 4 y = x - 8
the line parallel to y=x+7 has an equation y=x+k where k is some constant... now put x=6 and y=-2 and find k..
slope of y=x+7 is 1 so the line passing throw (6,-2) is parallel to y=x+7 so ,slopes are equal m1=m2 now equation of a line passing through (6,-2) and slope 1 is (y-y1)=m(x-x1) y+2=1(x-6) x-y-8=0
I don't under stand
so answer is y=x-8
yeah but I don't get how you did it
parallel lines have same slope....right?@lexi123479
as the line y=x+7 and the line we have to find are parallel they have same slopes
so find the slope of y=x+7
hence it is the slope of the line we have to find
so we got the slope and point is given with point slope form find the equation
did you get it
Join our real-time social learning platform and learn together with your friends!