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Solve 3x – 7y = 25 using matrices. 5x – 8y = 27 (25, 27) (27, 25) (-1, -4) (4, 1)
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\[\left[\begin{matrix}3 & -7\\5&-8\end{matrix}\right] \left(\begin{matrix}x \\ y\end{matrix}\right) = \left(\begin{matrix}25 \\ 27\end{matrix}\right)\] Now find the inverse of the first matrix and multiply.
11?
what 11?
that wat i got
Oh, it is the determinant(?)
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yah
Okay, do you know how to find the inverse of a matrix?
i make b and c negative right?
Inverse of \[\left[\begin{matrix}a & b \\c & d\end{matrix}\right]\] is \[\frac{ 1 }{\left| A \right| } \left[\begin{matrix}d & -b \\ -c &a\end{matrix}\right]\] where /A/ is the determinant.
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