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match the function
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what function?
Best response ever @FriedRice
lol
1+sec^2x sin^2x = sec^2x
cos^2x+sin^2x=1 so (if you divide both sides by cos^2x)... 1+tan^2x=sec^2x tan^2x=sec^2x-1 sec^2x/sec^2x-1=csc^2x sec^2x/tan^2x=csc^2x (1/cos^2x)/(sin^2x/cos^2x)=csc^2x (1/cos^2x)(cos^2x/sin^2x)=csc^2x (1/sin^2x)=csc^2x csc^2x=csc^2x
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hello?
thank you!
yw
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