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Mathematics 17 Online
OpenStudy (anonymous):

match the function

OpenStudy (anonymous):

what function?

OpenStudy (anonymous):

Best response ever @FriedRice

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

1+sec^2x sin^2x = sec^2x

OpenStudy (anonymous):

cos^2x+sin^2x=1 so (if you divide both sides by cos^2x)... 1+tan^2x=sec^2x tan^2x=sec^2x-1 sec^2x/sec^2x-1=csc^2x sec^2x/tan^2x=csc^2x (1/cos^2x)/(sin^2x/cos^2x)=csc^2x (1/cos^2x)(cos^2x/sin^2x)=csc^2x (1/sin^2x)=csc^2x csc^2x=csc^2x

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

yw

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