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Simplify: (-2i+√5)(-2i-√-5)?
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by distributive law (-2i+√5)(-2i-√-5) = -2i*-2i -2i*-(√-5) + √5* -2i + √5*(-√-5)
note i = √-1, so i^2 = -1
so -2i*-2i = 4 * i^2 = 4 * -1 = -4
and √-5 can be written √5 i
so it be -4+ sqr(5) i
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no it just be plus 5..right?
no - i was just helping you do the tricky bits you must simplify what i wrote in my first post
oh..
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