Question

confused please help for medal and fan (: posting below

Answer 1

\[\frac{ 4 }{ y-1 }+\frac{ 2 }{ 3 }=\frac{ 6 }{ y-1 }\]

Answer 2

Multiply both sides of the equation by \(y-1\):
\[(y-1)\left(\frac{4}{y-1}+\frac{2}{3}\right)=(y-1)\left(\frac{6}{y-1}\right)\\
4+\frac{2}{3}(y-1)=6\\
\frac{2}{3}(y-1)=2\\
y-1=2\cdot\frac{3}{2}\\
~~~~~~~~~\vdots\]