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Permutations Question HELP!!!! In how many ways can 7 people be arranged in a line if X and another particular person Y are on neither end?
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|dw:1373965285915:dw|
5 people in the middle can be arranged in 5! ways
and you can XY can be swapped in 2 ways
multiply both
oh its neither end ?
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yeh its neither end
then just subtract these from total permutations 7!
X and Y on either end = 2x5! X and Y on neither end = 7!-2x5!
thanks :D
yw !
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I want you be aware that, this solution assumed the question was asking us to find number of permutations in which, X and Y are not SIMULTANEOUSLY on either end
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