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Mathematics 11 Online
OpenStudy (chillout):

The remainder of x³ divided by x²-x+1 is A, and the remainder of x^2007 by x²-x+1 is B. Find A and B

OpenStudy (rsadhvika):

check the question once

OpenStudy (rsadhvika):

the phrase : The remainder of x³ divided A by x²-x+1 is... makes no sense

OpenStudy (chillout):

@rsadhvika, sorry. Was AFK and it was a mistype.

OpenStudy (rsadhvika):

finding A is easy right

OpenStudy (anonymous):

a is -1 b is -2007/x

OpenStudy (chillout):

Well, answer for B is -1. But A is right. Can you show the steps?

OpenStudy (anonymous):

ya wait

OpenStudy (anonymous):

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OpenStudy (anonymous):

did you get it

OpenStudy (chillout):

Yes, I did, thanks! Now I've got only to find B.

OpenStudy (anonymous):

what's the question for b

OpenStudy (chillout):

Well, your answer states that B = -2007/x. But here it says the answer is also -1.

OpenStudy (anonymous):

x^2007 by x²-x+1 is this the question

OpenStudy (chillout):

yes

OpenStudy (anonymous):

i couldn't find once check the question

OpenStudy (chillout):

http://www.studyjapan.go.jp/en/toj/pdf/08-006.pdf Here is the question. It is the question number 2. The answer is here: http://www.studyjapan.go.jp/en/toj/pdf/08-gakubu_answer.pdf. It is in page 5.

OpenStudy (chillout):

Well, I'm going to try. Wait a moment :)

OpenStudy (anonymous):

oh its x to the power of 2007 i thought its 2007x2

OpenStudy (chillout):

Yea, haha.

OpenStudy (anonymous):

as you got remainder -1 for x3 for every odd power you will get the same -1

OpenStudy (chillout):

And if it is even?

OpenStudy (chillout):

Is there a general rule?

OpenStudy (anonymous):

no but i remember this type of problems no one does division for such a long power they just use logic and shotcut's that's why they give a problem like x3 before it

OpenStudy (chillout):

K, I got it... Thanks.

OpenStudy (anonymous):

anytime

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