Question

A basketball was thrown from one end of a court to another. It had an initial upward velocity of 48 feet per second. How long did it take for the ball to hit the ground? Formula (h=v-16t^)

a.) 3 Seconds
b.)0.3 Seconds
c.)-3 Seconds
d.)-0.3 Seconds

Answer 1

v=velocity=48, h=height=0, t=time
h = vt – 16t^2
48t-16t^2=0
16t(3-t)=0
-t=-3
t=3 sec

Answer 2

Thank you so much :)

Answer 3

Anytime.