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how do i find the geometric mean between 4 and 25
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if b is the geometric mean between a nd c, then \(\large b=\sqrt{ac}\) here, a=4,c=25
multiply (in your head) then take the square root (again in your head)
can you show me how i would set it up as 2 fractions?
as a fraction ? yes, if b is the geometric mean between a and c, then \(\huge \dfrac{a}{b}=\dfrac{b}{c}\)
a and c is 4 and 25?
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absolutely :)
so i would set it up as 4/b=b/25 ?
correct, go on
and the sqrt of 4*25 is 10?
yes, it is. GM =10 is correct :) any doubts ?
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nope :) but what if instead the 25 was 1/4 as a fraction?
but what if ..... what ? i couldn't get you....
this a new question lol
ohh...i'll go there.. :)
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