Question

homogeneous equations
(x^2+y^2)dx+2xydy=0

Answer 1

im using y=vx dy=xdv+vdx
\[(x^2+(vx)^2)dx+2x(vx)(xdv+vdx)=0\]
then
\[x^2dx+v^2x^2dx+2vx^2(xdv+vdx)=0\]
finally
\[x^2dx+v^2x^2dx+2vx^3dv+2v^2x^2dx=0\]
stuck here and not sure if this is even right....

Answer 2

@Nurali does the work I did look formatted to you? normally it looks formatted for me but its not. Do you know how I can change it back?

Answer 3

@Nurali thanks a lot!

Answer 4

Anytime.

Answer 5

Please click best response.