Question

Equation of line that goes through (1,3) (-2,-3)
My options:
y=-2x+1
y=2x+1
y=1/2x-1

Answer 1

(x-x1)/(x2-x1) = (y-y1)/(y2-y1)
(x1, y1) = (1, 3)
(x2, y2) = (-2, -3)

Now substitute the above values in the formula:

(x-1)/(-2-1)=(y-3)/(-3-3)
(x-1)/-3=(y-3)/-6
-6(x-1)=-3(y-3)
-6x+6=-3y+9
6x-3y+9-6=0
6x-3y+3=0
3y=6x+3
Divide by 3
y=2x+1

Answer 2

Thank you(:

Answer 3

My Pleasure.