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how to solve: sin4x+sin2x=cosx
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do you want to prove it or want to solve it for the value of theta?
use sin2x=2sinx cosx 1+cos2x=2cos^2 x
use the identity : sinA + sinB = 2sin((A+B)/2)cos((A-B)/2)
let A = 4x and B = 2x see the equation above becomes 2sin3xcosx = cosx 2sin3xcosx - cosx = 0 factor out! cosx(2sin3x - 1) = 0 set each factor be zero then solve for x
Thanks RadEn, I was forgetting to factor the equation. It is solved now.
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you;re welcome
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