Question

Prove.

Answer 1

\[\Huge (x^2+a^2)(y")+xy'=0\]
if
\[\Huge y=\log(x+\sqrt{x^2+a^2})\]

Answer 2

I thought of taking x=atantheta
so..
\[\Huge y=\log(atan \theta+\sqrt{a^2\tan^2 \theta+a^2})\]
\[\Huge y=\log(a(\sec \theta+\tan \theta))\]

Answer 3

\[\LARGE y'=\frac{1}{a(\sec \theta+\tan \theta))}(\tan \theta(\tan \theta+\sec \theta \tan \theta)\]

Answer 4

y'=tan theta

Answer 5

@shubhamsrg sahi hai? any better mthd?

Answer 6

1 ques se bich me hi dusre ques pe kaha shift kar jate ho? :|

Answer 7

batao na :P

Answer 8

y'= tan theta me kaise simplify ho gaya? :|

Answer 9

kahan se nahi aya?

Answer 10

y'=1/acost ana chaiye tha na ?

Answer 11

haan sahi hai fir ? :| normal?

Answer 12

y'' = ?
and usme satisfy karwane ka try karo

Answer 13

ajaega na?:| ya normally better hota

Answer 14

aa jana chaiye

Answer 15

better method kaunsa hai

Answer 16

tumhara method as usual best hai :)

Answer 17

yahi to sunna tha :")