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help please find the 9th term of the sequence. a4=3/4 and a8=1/2 ; a9= ???
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Let a be the first term and d be c.d. tn=a+(n-1)d 3/4=a+(4-1)d=a+3d 1/2=a+(8-1)d=a+7d subtract to get the value of d and then a9=a8+d
i guess this is an arithmetic sequence?
i did this problem twice already and i got two different answers. i got 3/4 and the second time i got 1/2
i gave the the solution considering it as an arithmetic sequence. you can also solve it as any other sequence e.g.,geometric
is it arithmetic sequences you are studying istinkatmath1?
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yes @cwrw238
\[4d=\frac{ 1 }{ 2 }-\frac{ 3 }{ 4 }=\frac{ 2-3 }{4 }=-\frac{ 1 }{ 4 },d=-\frac{ 1 }{ 16 }\] \[a9=\frac{ 1 }{ 2 }+\frac{ -1 }{ 16 }=\frac{ 8-1 }{ 16 }=\frac{ 7 }{ 16 }\]
i got it thanks !(:
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