Question

what is the slope of the line that is perpendicular to the line that passes through the points (7,6) and (3,-4)

Answer 1

ok so what u do is:

Answer 2

m = y2-y1/x2-x1
= (-4-6)/(3-7)
=-10/-4
=5/2
therefore, as m(perp) x m = -1,
m(perp) = -2/5

Answer 3

Thank you so much!!!!!!!

Answer 4

You're welcome! :)

Answer 5

perpendicular slopes have negative reciprocals- remember that

Answer 6

Ok I'll try

Answer 7

:)