Question

Part a.) Write the equation of the line that has a slope of -2 and a y-intercept of -6. (5 points)

Part b.) Write the equation of the line that passes through the point (6, -2) and has a slope of -2/3. (5 points)

Answer 1

part a) y-intercept slope "y=mx+b"

y=mx+b m=slope b=y-intercept

slope -2

y-intercept -6

so you put your numbers into the equation

y=-2x-6 and that's your answer

part b) you need point slpe form which is y-y1=m(x-x1)

m= slope, and you have (6,-2) which is your (x1,y1)

put them into your equation

y-(-2)=-2/3(x-6) or y+2=-2/3(x-6)

multiply -2 on the left and the 3 to rigth

y-4=3x-18

add 4 both sides

y=3x-14 that's you answer