Question

How high is a ball after 4 seconds if it is thrown upward at a velocity of 117 m/sec. and it started off at a height of 38 m?

250 m

251.89 m

427.6 m

736.42 m

Answer 1

do you know the equation for the height?

Answer 2

um no

Answer 3

then you can't do it

Answer 4

is it in your book?

Answer 5

hold on is it h=-16x^2+c

Answer 6

what would be in feet, but it looks like you have meters

Answer 7

i think it is \(h(t)=-4.9t^2+v_0t+h_0\)

Answer 8

in your case
\[h(t)=-4.9t^2+117t+38\] and you need to find
\[h(4)\]

Answer 9

wered you get 4.9?

Answer 10

i googled it

Answer 11

i know that if you work in feet it is
\[h(t)=-16t^2+v_0t+h_0\] but i forgot what it was if you are working in meters, so i googled it

Answer 12

oh ok..