Question

Solve these compound inequalities??

Answer 1

basically just solve for x.

Answer 2

not exactly

Answer 3

\[\sqrt{3x+9}<3\] before we begin we know \(3x+9\geq 0\) or \(x\geq -3\)

Answer 4

then you can square both sides and get
\[3x+9<9\] making \[x<0\]

Answer 5

solution will be \([-3,0)\)

Answer 6

I just did this one and got the same solution! (:

Answer 7

@satellite73 the problem is asking me to put >,<, or <(or equal to), >(or equal to) so would it be x<(or equal to) 0?