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Mathematics 22 Online
OpenStudy (anonymous):

find values of x for |3x+1|<1.

OpenStudy (lncognlto):

Square both sides of the equation and solve for x.

OpenStudy (anonymous):

Can you try to type out the process,I do not quite understand it.

OpenStudy (lncognlto):

(3x + 1)^2 < 1^2 3x^2 + 6x + 1 < 1 3x^2 + 6x < 0 3x(x+2) < 0 Now we need a table

OpenStudy (lncognlto):

|dw:1374068376772:dw|

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