okay i got the distance which it is 38499*10^15 but how am I suppose to know if it is reasonable?
Compute the distance Erica will run if she continues using the formula, y = 3(1.1)x, for 52 weeks (one year). Does this distance seem reasonable?
yes
no

Question

okay i got the distance which it is 38499*10^15 but how am I suppose to know if it is reasonable?
Compute the distance Erica will run if she continues using the formula, y = 3(1.1)x, for 52 weeks (one year). Does this distance seem reasonable?
yes
no

anonymous · Answer

@vinnv226 please help me

anonymous · Answer

Can you give any more information on this function? For example, what do y and x represent, including units?

anonymous · Answer

x=days later y=distance in miles?

anonymous · Answer

Ok, so:
$$52 weeks = 52 \times 7 days=364 days$$Plug in 364 for x in the equation:
$$3(1.1)x$$
$$3.3x$$
$$3.3(364)=1201.2 miles$$Assuming your equation is written correctly.

anonymous · Answer

yea but how would u know if its a reasonable distance? @vinnv226