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see of you can write 1296 as a power of 6
X=4 :)
\[\log_61296=x\] \[6^x=1296\] what x makes 6^x=1296
is that \[e\ln x=2\]
yes
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\[\huge \ln x=\frac{2}{e}\] \[\huge e^{\ln x}=e^{\frac{2}{e}}\] \[\huge x=e^{\frac{2}{e}}\]
when you post a new question you shud close the old one and start a new question
so whats the answer? whats xxxx
?????
u sure bcuz i cnt seam to type that in as an answer
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\[e \approx 2.6\] use a calculator to evaluate that
i think then your question shud be \[\huge e^{\ln x}=2\] \[\huge x=2\]
thanks!!!!
but ur going to have to keep helping me
1/8)8 (17
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