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Solve: 3(x + 4) greater than or equal to x - 2 x greater than or equal to -7 x greater than or equal to 7 x less than or greater to -7 x greater than or equal to -3
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\[3(x+4) \ge x-2\]Expand it \[3x+12 \ge x-2\]Now subtract \(x\) from both sides, subtract 12 from both sides, giving you \(x\) term on the left and numeric term on the right. If there's a number in front of \(x\), divide both sides by that number, changing the direction of the inequality if the number is negative.
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