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log base 5 (x-4)=0 how do i solve this?
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log(1) = 0
can you explain how you got that?
if need be, base 5 each side x-4 = 1
Convert it into exponential form
its a property of logs ....
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X=5, by converting 5^0=x-4 as 5^0is 1
let there be a function such that: L(ab) = L(a) + L(b) define a*1 L(a*1) = L(a) + L(1) L(a) = L(a) + L(1) L(a) - L(a) = L(1) 0 = L(1)
Got it! thank you so much!
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