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What is the equation of the line that passes through the point (4, 1) and has a slope of 5?
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if you plug in all that imformation into the equation \[y -y_{1} = m (x-x_{1})\] then solve for y you will have a standard y = mx +b
Is the answer y = 5x - 3
think you might have pluged in wrong :O did you start out with: \[y - 1 = 5(x -4)\]
Ok i think i found my mistake
y = 5x - 1
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i will do it step by step again :) \[y- 1 = 5(x-4)\]\[y -1 = 5x - 20\]\[y = 5x - 19\] if you see a mistake plz fix it :)
Oh... I know where I messed up,
Thank you! :)
no problem :)
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