Question

help

Answer 1

@dumbcow

Answer 2

OK !
the equation is :
\[8-2x^2=(x+2)^2-7\]
So, we expend the brackets first :
\[8-2x^2=x^2+4x+4-7\]
so :
\[8-2x^2=x^2+4x-3\]
The we transform all the terms in the right side to the left side
\[8-2x^2-x^2-4x+3=0\]
So :
\[-3x^2-4x+11=0\]