Question

Write the expression as a sum and/or difference of logarithms. Express powers as factors. log3(9x)

"Log 3 of 9 x"

Answer 1

@Ashleyisakitty @MathSucks42 @hartnn

Answer 2

Please help!

Answer 3

its \(\log_39x\) right ?
lets first use the easier property,
\(\log_ab\times c=\log_ab+\log_ac\)

so what about
\(\log_39\times x\)

Answer 4

My mom is gone and I'm doing her college test for her! SHE NEEDS THIS OR SHE FAILS!

PLEASE, I DONT KNOW ANY OF IT AND I HAVE TO DO THIS WHILE SHE IS AT WORK! PLEASE PLEASE :((((

Answer 5

Yes, it is.

Answer 6

Hartnn, I don't understand any of it. It's 11 and she has to have it done by 12. This is NOT my homework, it is hers, and if she doesn't get it, then she owes the school back a lot of money. PLEASE HELP me and my family!

Answer 7

Hmmm idk, but i doubt any parent (mom or dad) would put their son or daughter to do their "college test" for them.

Answer 8

If its hers, then she might have been a bit more organized and responsible to finish her school work.

Answer 9

She is at work. You have to believe me. It's 11:02 and I'm freaking out because I'm only half way done. I'm a common user at OpenStudy and would NEVER pull something like this. PLEASE just help! :(

Answer 10

Look, if you could just help explain it to me I MIGHT get it. But I'm really having trouble. I'm only in Algebra I

Answer 11

So how do you have half of it done?

Answer 12

Because I've been using Mathaway and Yahoo Answers, and some of it I can sort of understand

Answer 13

Wolfram isn't helping with this one!

Answer 14

Well you doing this type of math that you have not learned and do not understand, and thus asking for help, it wont help because you don't know what we are talking about, nor the terms. Yes, its great that you might want to learn, but this way is not very clever; plus its your moms test.

Answer 15

Please don't do this to me :(

I'm really desperate. @hartnn , could you just try to explain it again, please!!!

Answer 16

I would say that you are capable of doing this, and it is actually your test.

Answer 17

Just to point out, you are not much of a "common OS user" .

Answer 18

ok, simply plug in a=9, b=x
\(\log_a(b\times c)=\log_ab+\log_ac\)
\(\log_3(9\times x)=...?\)

Answer 19

***b=9,c=x

Answer 20

It is my mom's. Here is a picture!

http://prntscr.com/1g2jb0

Look, can we stop arguing and just try to explain.

Answer 21

so log9(x * c) = log9 + x + log9^c ?? Is that it? I'm so confused.