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a flat rectangular piece of aluminum has a perimeter of 58 inches. the length is 7 inches longer than the width. find the width.
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say length = l, width = w
do u remember the formula for 'perimeter of rectangle' ?
P=2L+2W
yes ! 2L+2W = 58 -------------(1)
let x+7 = length let x = width add x+x+(x+7) + (x+7) =4x +14 =?
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it is given that length is 7 inches longer than the width. L = W + 7 -----------(2)
two equation, two unknowns, you can solve them
2(x+7) + 2(x) =58 solve for x
x=11
?
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Hint: x = side length
im getting 11 for x
11*4 = 44 44 + 14 = 58
If you wanted to use x for length then you would represent "x-7 for the side, it can be done either way
got it! thank you!
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