Question

Which quadratic equation has its vertex at (-3,5) and opens down?
F: y=(x-3)^2+5
H: y=(x+3)^2-5
G: y=-(x+3)^2+5
J: y=-(x-3)^2+5

Answer 1

since x = -3 & y = 5 the equation is y = ax^2 + c
= -3^2 + 5

Answer 2

so your ans is F

Answer 3

thanks

Answer 4

any time :)