Question

Simplify, leaving as little as possible inside a solute-value signs.
I x^2/-y I

and

I-8x^2/ 2x I

Answer 1

sorry i meant absolute- value

Answer 2

x^2 >= allways
so
|x^2| is redundant
so take it out
x^2/|-y|

Answer 3

what do you mean x^2 = always?

Answer 4

same logic on the second
(4x^2)||x|

Answer 5

x^2 is always greater than or equal to zero

Answer 6

that should say (4x^2)/|x|

Answer 7

the answer in my book for the second one was 4IxI? can you do more to that problem? and also how did you go from 8 to 4?

Answer 8

nvm i get the 4 to 8

Answer 9

I-8x^2/ 2x I = |-8/2|*|x^2/x| = |-4||x| = 4|x|