Question

Another system of equation.. Need Help anyone?
x+y+z=7
x+2y-z=0
x+5y=7

Answer 1

Help anybody??

Answer 2

x+y+z=7 (1)
x+2y-z=0 (2)
x+5y=7 (3)

(3) gives
y=1/5(7-x)

(2) gives
x+2/5(7-x)-z=0
3/5x+14/5-z=0
z=3/5x+14/5

(1) gives
x+1/5(7-x)+3/5x+14/5=7
x=2

y=1/5(7-x)
y=1

z=3/5x+14/5
z=4

The system of equations has got an unique solution.
x=2
y=1
z=4

Answer 3

x+y+z=7----(1)
x+2y-z=0---(2)
x+5y=7-----(3)

add '1' and '2'

2x+3y=7
2x=7-3y
x=7-3y/2----(4)

put 'x' in equation '3'
7-3y/2+5y=7
7-3y+10y=14
7y=7
y=1

put 'y' in equation '4'
x=7-3/2
x=4/2
x=2
put x and y in equation '1'
1+2+z=7
z=4

Answer 4

Thank you!!

Answer 5

Anytime.