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What is the length of the diameter of the base of a cylinder if its volume is 768Pi cubic inches and its height is 12 inches
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V = pi*r^2*h 768pi = pi*r^2*12 solve for r, then use the value of r to find d = 2r
I dont know how to solve for r
768pi = pi*r^2*12 768pi/pi = pi*r^2*12/pi 768 = 12r^2 12r^2 = 768 how about now?
12r/12=27.7/12 r=2.3 Am i right?
12r^2 = 768 r^2 = 768/12 r^2 = 64 r = ???
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r=8 !
yep
so the answer is 8?
correct
oh wait
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Thankssss
the radius is 8
the diameter isn't 8 though
oh, the diameter is 16. d=2r
yep you got it
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