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OpenStudy (anonymous):
Identify the vertex of the parabola with the quadratic equation>>>y=6x^2-72x+220<<
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OpenStudy (isaiah.feynman):
Pretty easy, (6,364)
OpenStudy (anonymous):
Its (6,4) or (72,220)
OpenStudy (anonymous):
Do you know how to convert from standard form to vertex form?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
So vertex form is y-y=(x-x)^2 If you are able to get your original equation to that, your vertex coordinates would be the second x and second y.
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OpenStudy (isaiah.feynman):
Oh the answer is (6,4) I omitted the x with the 72.
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