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please help 1 medal and fan If BC = 5.3, CD = 8.8, and AD = 14.3, find AB to the nearest tenth. a.8.6 b.23.7 c.3.3 d.1.6 https://rialto5819-ehs-pps.gradpoint.com/Resource/2146263,72F,0,0,0,0,0/Assets/testitemimages/geometry_a/similarity/mc095-1.jpg
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This is the Triangle Angle Bisector Theorem at work. If a ray bisects an angle of a triangle, it divides the opposite side into segments proportional to the lengths of the other two sides.
BC is to CD as AB is to AD 5.3/8.8 = AB/14.3 So cross multiply (Means-Extremes Property) and solve for AB. @knowel
If the AB is distracting, let AB = x. Then 5.3/8.8 = AB/14.3 becomes 5.3/8.8 = x/14.3
8.6
That is what I got.
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