The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both decreased by 2, the fraction is now equal to .

If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?

5n = 3d and n - 2 = 2d - 4
5n = 3d and 2n - 4 = d - 2
3n = 5d and 2n - 4 = d - 2

Question

The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both decreased by 2, the fraction is now equal to .

If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?


5n = 3d and n - 2 = 2d - 4
5n = 3d and 2n - 4 = d - 2
3n = 5d and 2n - 4 = d - 2

anonymous · Answer

we will never solve this problem since u miss a part

anonymous · Answer

the fraction is now equal to .: ???????????????????????????????

anonymous · Answer

my bad its $$\frac{ 1 }{ 2}$$

anonymous · Answer

isnt it the second one?

anonymous · Answer

for the first equation we have
(n/d)=(3/5)
the second equation is
( (n-2)/(d-2) ) = 1/2