Question

(-2x+6) ^ 1/5 = (-8+ 10x)^1/5

Answer 1

\[(-2x+6) ^ {\frac{1}{5}} = (-8+ 10x)^ {\frac{1}{5}} \]
Since powers on both sides are eqaul
therefore
\[(-2x+6) = (-8+ 10x) \rightarrow -2x+6=-8+10x \rightarrow 6+8 =10x+2x\]
\[14 =12x \rightarrow x =\frac{14}{12}\]
\[x =\frac{7}{6}\]