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cos theta - 1 =0
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\(\cos(\theta)=1\) is a start
what is the question?
I believe this is my way of explaining ALL odd multiples of pi cos(theta) +1 = 0 =>cos(theta)= -1=cos(pi) =>(theta)= 2n(pi)+pi n = 0,1,2,3,4...............................… =>(theta)= pi,3(pi),5(pi),7(pi)....................…
find all solutions to the equation. write your answer in radians in terms of pi. Then they have a whole bunch simples like\[k \in Z\]
\[k\in\mathbb Z\] mean that k is a integer ie \(k=\{...,-3,-2,-1,0,1,2,3,...\}\)
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