Question

1.) Write the equation of the line perpendicular to the line x - 5y = -10 and passing through the point (2,5).

2.) Write the equation of the line parallel to the line 10x - 5y = 8 and passing through the point (2,4).

3.) Write the equation of the line parallel to the line 4x + y = -1 and passing through the point (5,0).

4.) Write the equation of the line parallel to the line 4x + 2y = 5 and passing through the point (-3,5).

5.) Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).

Answer 1

A) y = -2x - 1
B) y = -4x + 20
C) y = -5x + 15
D) y = -3x + 14
E) y = 2x

Answer 2

I will do a perpendicular and a parallel to show you how to do it...

First you need to put the equations in y = mx + b form
1. x - 5y = -10
-5y = -x - 10 (multiply the equation by -1)
5y = x + 10 (now divide by 5)
y = 1/5x + 2
Perpendicular lines have slopes that are the negative reciprocal. So the slope will be -5.
y - y1 = m(x - x1) using slope -5 and points (2,5)
y - 5 = -5(x - 2)
y - 5 = -5x + 10
y = -5x + 10 + 5
y = -5x + 15 (answer C)

2. 10x - 5y = 8
-5y = -10x + 8 (multiply by -1)
5y = 10x - 8 (divide by 5)
y = 2x -8/5
Parallel line have the same slope, so the slope will be 2.
y - y1 = m(x - x1) using slope 2 and points (2,4)
y - 4 = 2(x - 2)
y - 4 = 2x - 4
y = 2x - 4 + 4
y = 2x (answer E)

If you have any more problems with the rest of them, just tag me :)

Answer 3

Thank you!!

Answer 4

do you understand enough to do the other problems ?

Answer 5

Yes! Thanks!

Answer 6

glad I could help :)