Question

If p varies inversely as the square root of q, and p = 12 when q = 36, find p when q = 16.

Answer 1

\(\bf p = \cfrac{n}{\sqrt{q}}\\
\text{when p=12, q =36}\\
12 = \cfrac{n}{\sqrt{36}}\)

Answer 2

so if you solve for "n", what would that be?

Answer 3

p varying inversely to something, means, equals the inverse of something
something's inverse is 1/something