if the base of a triangle is 10 and the height is 12 what is length of the other line hypotenuse line
Is your triangle a right triangle?
heres a picture of what I was given and the whole question was... TV = 20 and CU = 12. Find the length of UV. Show equations and all work that leads to your answer. I just guessed base was 10 and height was 12
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Use Pythagoras's theorem from here: \[a ^{2}+b ^{2}=c ^{2}\] where TU is your hypotenuse
that cant be right a2+b2=c2 would look like 10squared which is 100 and 12squared which is 144 it says add them together which is 59,536 theirs no way that's right
If we added 100 to 144, we'd get 244. So, \[c ^{2} = 244\] what is c?
sorry once you square that though you get 59,536
Ahhhhh I see what happened now. Easy fix we just need to square root the 244 not square it. So, what the square root of 244 \[\sqrt{244} = ?\]
15.62
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