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Mathematics 29 Online
OpenStudy (foreverandalways13):

what value of c makes this a perfect square? 4x^2+20x+c

OpenStudy (foreverandalways13):

someone?

OpenStudy (foreverandalways13):

@amistre64

OpenStudy (foreverandalways13):

@Luigi0210

OpenStudy (foreverandalways13):

@jdoe0001

OpenStudy (foreverandalways13):

@ashleyvee

OpenStudy (foreverandalways13):

nevermind...its 25:) figured it out

OpenStudy (jdoe0001):

$$\bf 4x^2+20x+c\\ \text{grouping the "x"s and common factoring it}\\ (4x^2+20x) +c\\ \text{keep in mind a perfect square trinomial is}\\ (a\pm b)^2 = a^2\pm 2ab + b^2\\ (4x^2+20x+\square ?) +c\\ \color{blue}{\text{or as in }}\\ ((2x)^2+2(x)(\square ?)+\square?^2)+c $$ so what number there do we need to get the perfect square triinomial?

OpenStudy (foreverandalways13):

thanks...

OpenStudy (jdoe0001):

hmm, I may have overdone but anyhow

OpenStudy (jdoe0001):

should be just => \(\bf ((2x)^2+2(x)(\square ?)+\square?^2)\) and THAT VALUE will be "c"

OpenStudy (foreverandalways13):

its ok..

OpenStudy (foreverandalways13):

you have a medal! lol

OpenStudy (jdoe0001):

hheehe, so, did you get the number?

OpenStudy (foreverandalways13):

yeah 25...right?

OpenStudy (jdoe0001):

25, root of 25 is 5 2(x)(5) = 10x but you'd need 20x

OpenStudy (foreverandalways13):

ok thanks...got it...next question:) im in the middle of a really long math assignment:P

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