Question

Evaluate log(subscript 5)121 when log(subscript 5)3=0.683 and log(subscript 5)7=1.209

Answer 1

\[This is the equation \log_{5} 121\]

Answer 2

ehehe

Answer 3

methinks use Das Kalkulatorr

Answer 4

ohh,... only base 10... well, use the change of base rule, if that's all that is
\(\bf log_5121\cfrac{log_{10}121}{log_{10}5}\)

Answer 5

i got 2.98

Answer 6

that it's then

Answer 7

Thank you

Answer 8

btw I forgot the equal sign, so => \(\bf log_5121=\frac{log_{10}121}{log_{10}5}\)

Answer 9

yw