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Mathematics 12 Online
OpenStudy (anonymous):

Use the cofunction identities to evaluate the expression below

OpenStudy (anonymous):

Where is the expression ?

OpenStudy (anonymous):

OpenStudy (anonymous):

We have : \[\sin^257^\circ+\sin^227^\circ+\sin^233^\circ+\sin 63^\circ~~\\=\sin^257^\circ+\sin^227^\circ+\sin^2(90^\circ-57^\circ)+\sin^2(90^\circ-27^\circ)\\=\sin^257^\circ+\sin^227^\circ+\cos^257^\circ+\cos^227^\circ\\=(\sin^257+\cos^257^\circ)+(\sin^227+\cos^227^\circ)\\=1+1=2\]

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