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PLEASE HELP!!! Solve 4^x = 12 a.) x ≈ 0.27 b.) x ≈ 0.56 c.) x ≈ 1.79 d.) x ≈ 19.93
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None of the answers are correct.
i copied and pasted the question and answers directly form the site.
sry but these are all not it
That's better.
\(4^x = 12\) Take log of both sides: \(\log{4^x} = \log{12}\) Use law of logs: \(x \log {4} = \log{12} \) Solve for x
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One of the answers is correct.
Ah yes! I must have missed the power sign! [problem with computers and maths!] Yes, one of the answers is correct!
@sarahusher You didn't miss the power sign. It was added later.
\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\] and a calculator
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looks to be about 1.79...
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