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Let X represent the outcome of a wheel of fortune that has whole numbers 0 to 50 on different slots. What is the expected outcome? A. 50 B. 25 C. 10 D. 0
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\(\frac{1+2+3+...+50}{51}\)
since \(1+2+3+...+50=\frac{50\times 51}{2}\) you get \(\frac{50}{2}=25\)
which i am willing to bet, you could have guessed at
probability is not my thing i cant get the hang of it.
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