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could somebody please check my answer if it is correct. the question is: Find the derivative of y=e^-5x cos(4x-7)
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f'(x) = e^-5x [-4sin(4x-7) - 5cos(4x-7)]
you can take -1 out as a common factor as well but otherwise it looks good to me
looks correct to me! good :)
thanks guys i really appreciate it
Or bury the -1 by writing as \[e^{-5x}[4\sin(7-4x)-5\cos(7-4x)]\]
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