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A baseball player hits a ball. The ball leaves the bat with an initial upward velocity of 64 feet per second. How many seconds will it take for the ball to hit the ground? Use the formula in which the height above ground after t seconds is given by the quadratic function h = –16t2 + vt, where h represents the height of the object in feet, and v represents the object's initial velocity in feet per second. 4 seconds 8 seconds 0 seconds 1 of a second 16
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solve 0 = -16t^2 + 64t
?
u had to find when h=0 so in the formula u must make h=0 also v= 64 the problem says that
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