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Solve the following system of equations. 3x + 2y - 5 = 0 x = y + 10
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put x=y+10 into 1st equation...
given x=y+10 so in another equation if we replace the value of x we get 3(y+10)+2y-5=0 =>3y+30+2y-5=0 =>5y+25=0 =>5y=-25 =>y=-5 now in another equation we are gonna replace the value of y x=-5+10 =>x=5
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