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simplify: 1/x+h - 1/x
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is it\[\frac{ 1 }{ x }+h-\frac{ 1 }{ x }\]?
No its 1 over x+h
1/x+h-1/x =>x-x-h/(x+h)x =>-h/x^2+hx
\[\frac{ 1 }{ x+h}-\frac{ 1 }{ x }\] \[\frac{ x-(x+h) }{ x(x+h) }\] \[\frac{ -h }{ x(x+h) }\]
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