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Mathematics 16 Online
OpenStudy (anonymous):

Help with probablilty question: A sample space consists of five simple events, E1,E2,E3,E4,E5 If P(E1)=P(E2)=0.15, P(E3)=0.4, AND P(E4)=2P(E5), find the probablilty of E4 AND E5

OpenStudy (anonymous):

P(E4) = 2P(E5) and you also know that P(E4) + P(E5) = 0.3 since events 1, 2 and 3 add to 0.7 a) Using algebra, you can find P(E4) = .2 and P(E5) = .1 from the above equations.

OpenStudy (anonymous):

so i set up a system? and then solve it

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

thanks

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