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Mathematics 13 Online
OpenStudy (anonymous):

Find the standard form of the equation of the ellipse with the following characteristics.

OpenStudy (anonymous):

OpenStudy (anonymous):

whats the equation???

OpenStudy (anonymous):

you cant even see that

OpenStudy (anonymous):

ANSWER CHOICES: (x^2/144)+(y^2/119)=1 (x^2/144)+(y^2/25)=1 (x^2/25)+(y^2/144)=1 (x^2/576)+(y^2/25)=1 (x^2/576)+(y^2/551)=1

OpenStudy (anonymous):

click on it...

OpenStudy (anonymous):

Woah lol what math is this im only in pre algebra but i know mot but not this srry

OpenStudy (amistre64):

what is half of 24?

OpenStudy (amistre64):

the foci are along the major axis; since the given information has the x parts of the foci modified; the half the axis length is under the x parts

OpenStudy (amistre64):

that narrow it down to 2 options

OpenStudy (amistre64):

the rest is in determining the remaining under y part .... f^2 + b^2 = v^2 might be a good way of looking at it f = 5, v = half of 24 from the given information; leaving b^2 to go under y

OpenStudy (amistre64):

144 -25 ---- 119 looks good to me

OpenStudy (anonymous):

so its a?

OpenStudy (anonymous):

@amistre64 so its choice a?

OpenStudy (amistre64):

i would say that "a" includes all the parts that i rambled on about, yes

OpenStudy (anonymous):

thanks!

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